If an IOExeption
occurs in the try{}
block,
what happens?
Execution of this method stops and the method throws
the IOExeption
up to its caller.
finally{}
block
If an IOExeption
occurs in this program, it immediately
looses contol.
The exception is thown to the method that called it, which in this case is the
Java run time system.
For this program, execution will halt.
By using a finally{}
block, you can ensure that some statements
will always run, no matter how the try{}
block was exited.
Here is the try/catch/finally{}
structure.
try { // statements, some of which might // throw an exception } catch ( SomeExceptionType ex ) { // statements to handle this // type of exception } .... // more catch blocks catch ( AnotherExceptionType ex ) { // statements to handle this // type of exception } finally { // statements which will execute no matter // how the try block was exited. } // Statements following the structure
There can only be one finally{}
block, and it must follow
the catch{}
blocks.
try{}
block exits normally (no exceptions occurred), then
control goes directly to
the finally{}
block.
After the finally{}
block the statements following the
structure get control.
try{}
block exits because of an exception which
is handled
by a catch{}
block, first
that block executes and then control goes to
the finally{}
block.
After the finally{}
block executes,
the statements following the
structure get control.
try{}
block exits because of an exception which
is NOT handled
by a catch{}
block, control goes directly to
the finally{}
block.
After the finally{}
block executes,
the exception is thrown to the caller
and control returns to the caller.